Question

3.0 moles of nitrogen is reacted with 11.0 moles of hydrogen to produce ammonia according to the chemical equation shown below. Which one of the following statements is false?
N2(g) + 3 H2(g) → 2 NH3(g)
a. Hydrogen is the excess reactant.
b. 2.0 moles of hydrogen are left over.
c. 12.0 moles of ammonia are produced.
d. Nitrogen is the limiting reactant.​

Answer 1

Answer:

c

Explanation:

From the equation, we can say that we need thrice the number of hydrogen than that of nitrogen

we are given 3 moles of nitrogen and 11 moles of hydrogen

but thrice the number of moles of nitrogen is 9, hence we have hydrogen in excess or Hydrogen is the excess reagent

Since we had 11 moles of Hydrogen and we only needed 9, 2 moles of hydrogen are left over

From the equation, we can see that the moles of ammonia formed will be twice the moles of nitrogen

Since 3 moles of nitrogen are used, the reaction will give us 6 moles of Ammonia and NOT 12 moles, therefore c is the correct answer

Since we have hydrogen in excess, our reaction is being limited because we have less Nitrogen, Hence Nitrogen is the Limiting Reagent

Answer 2

Option C is the only false statement

The false statement is that "12.0 moles of ammonia are produced"

According to the equation of reaction:

N₂  +  3H₂  >>>>>  2NH₃

1  mole of N₂ reacts with 3 moles of H₂

3 moles of N₂ will react with 9 moles of H₂

Since 3 moles of N₂ is said to react with 11 moles of H₂ (instead of 9 moles of H₂), H₂ is in excess by 2 moles. That is, N₂ is the limiting reactant.

Since N₂ is the limiting reactant:

1 mole of  N₂ produces 2 moles of NH₃

3 moles of N₂ will produce 6 moles of NH₃

Therefore, we can conclude that:

• Hydrogen is the excess reactant

• 2.0 moles of hydrogen are left over

• Nitrogen is the limiting reactant

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