Question

solve for w k=2b-5w/3k

Answer 1

$k = \frac{2b - 5w}{3k}$
$3k^{2} = 2b - 5w$
$3k^{2} + 5w = 2b$
$5w = 2b - 3k^{2}$
$w = \frac{2}{5}b - \frac{3}{5}k^{2}$

Answer 2

Answer:

b = $\frac{2b - 3k^{2} }{5}$

Step-by-step explanation:

To solve for w in this equation;

k = $\frac{2b - 5w}{3k}$

This implies we have to make w the subject of the formula.

To make w subject of the formula, first we cross multiply.

3k  × k  =  2b  -  5w

3k²  =   2b   -5w

Now we will subtract  2b from both- side of the equation

3k²   - 2b  = -5w

we want to make the right hand side of the equation positive, to do that , we will just multiply through by minus sign.  The equation becomes;

-3k²   +   2b   = 5w

We can rearrange the equation;

2b -  3k²   =    5w

5w  =  2b  - 3k²

Then we will now divide both-side of the equation by 5

$\frac{5w}{5} = \frac{2b - 3k^{2} }{5}$

In the left side of the equation, the 5 at the  numerator will cancel out the 5 at the denominator.

Hence;

w  =   $\frac{2b - 3k^{2} }{5}$