Question

how many grams of nh3 can be produced from 3.72 mol of n2 and excess h2.

Answer 1

N₂       + 3H₂ ⇒ 2NH₃
1mol       :         2mol
3,72mol  :         7,44mol

n = 7,44mol
M = 17g/mol

m = n * M = 7,44mol * 17g/mol = 126,48g