14. Find the value of x if QS bisects PQR and
mZPQR = 82.
(10.x + 1)
S
R

Answer:
x = 4
Step-by-step explanation:
Since, QS bisects [tex] \angle PQR[/tex].
[tex]\therefore m\angle PQS = \frac{1}{2} \times m\angle PQR\\
\therefore (10x + 1)\degree = \frac{1}{2} \times 82\degree \\
\therefore (10x + 1)\degree = 41\degree \\
\therefore 10x + 1 = 41 \\
\therefore 10x = 41 - 1\\
\therefore 10x = 40\\
\therefore x = \frac{40}{10} \\
\huge \orange {\boxed {\therefore x = 4}} [/tex]