Respuesta :
Answer:
1.17 M
Explanation:
Step 1: Given data
Molar concentration of Li₃PO₄: 0.390 M
Step 2: Write the reaction for the dissociation of Li₃PO₄
Lithium phosphate is a strong electrolyte that dissociates according to the following equation:
Li₃PO₄(aq) ⇒ 3 Li⁺(aq) + PO₄³⁻(aq)
Step 3: Calculate the molar concentration of lithium ions
The molar ratio of Li₃PO₄ to Li⁺ is 1:3. The molar concentration of Li⁺ is 3/1 × 0.390 M = 1.17 M.
Considering the definition of strong electrolyte, the molar concentration of Li⁺ is 1.17 M.
An electrolyte is a substance that, when dissolved in water, gives rise to the formation of ions.
Electrolytes can be weak or strong, depending on whether they are partially or fully ionized or dissociated in aqueous medium.
A strong electrolyte is any substance that, when dissolved in water, exclusively causes the formation of ions with a practically irreversible dissolution reaction. That is, it is a solute that completely dissociates into ions in solution.
Lithium phosphate is a strong electrolyte that dissociates according to the following equation:
Li₃PO₄(aq) ⇒ 3 Li⁺(aq) + PO₄³⁻(aq)
From the balanced equation, you can observed that:
1 mole of Li₃PO₄ produced 3 mole of Li⁺.
Therefore, 0.390 M Li₃PO₄ will produce = 3 × 0.390 = 1.17 M Li²⁺
In summary, the molar concentration of Li⁺ is 1.17 M.
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