The number f of miles a helicopter is from its destination x minutes after takeoff is given by f (x)=40-2x. The number f of miles a commercial jet is from its destination x minutes after takeoff is shown in the graph below.

The number f of miles a helicopter is from its destination x minutes after takeoff is given by f x402x The number f of miles a commercial jet is from its destin class=

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Answer:

Step-by-step explanation:

Function 'f' represents the number of miles (y-values) covered by the helicopter in 'x' (x-values) minutes.

f(x) = 40 - 2x

For x = 0,

f(x) = 40 miles

For f(x) = 0,

0 = 40 - 2x

x = 20 minutes

This shows that helicopter traveled 40 miles in 20 minutes.

Similarly, given graph shows distance covered by the jet on y-axis and duration of flight on x-axis.

For x = 0,

f(x) = 500 miles

For f(x) = 0,

x = 100 minutes

Commercial jet traveled 500 miles in 100 minutes.

The total distance and time taken for each flight are illustrations of intercepts.

  • The helicopter traveled 40 miles in 20 minutes
  • The commercial jet traveled 500 miles in 100 minutes

We have:

[tex]x \to[/tex] minutes

[tex]f(x) \to[/tex] miles

Helicopter

[tex]f(x) = 40 - 2x[/tex]

Set f(x) to 0, to calculate the x-intercept

[tex]0 = 40 - 2x[/tex]

Collect like terms

[tex]2x = 40[/tex]

Divide by 2

[tex]x =20[/tex]

Set x to 0, to calculate the y intercept

[tex]f(x) = 40 - 2x[/tex]

[tex]f(0) = 40 - 2 \times 0[/tex]

[tex]f(0) = 40[/tex]

This means that, the helicopter traveled 40 miles in 20 minutes

Commercial Jet

From the graph, the intercepts are:

[tex](x_1,y_1) = (100,0)[/tex] --- the x-intercept

[tex](x_2,y_2) = (0,500)[/tex] --- the y-intercept

This means that, the commercial jet traveled 500 miles in 100 minutes

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