Question

Container A has 800 ml of water and is leaking 6 ml per minute.
Container B has 1000 ml and is leaking 10 ml per minute.
Let m represest the number of minutes the contains are leaking.

How many minutes, m, will it take for the two containers to have the same amount of water?

Answer 1

The correct answer would be 50 minutes.

Answer 2

It will take 50 minutes for the two containers to have the same amount of water.

Based on the information given, the equation to solve the question will be:

800 - 6m = 1000 - 10m

Collect like terms

-6m + 10m = 1000 - 800

4m = 200

Divide both side by 4

4m/4 = 200/4

m = 50

Therefore, it'll take 50 minutes.

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