Question

What is the equation of a line perpendicular to 3X+6Y= -3 and passes through the points (1,-5)

Answer 1

Answer:

Step-by-step explanation:

6y = -3x - 3

y = -1/2x - 1/2

perp. 2

y + 5 = 2(x - 1)

y + 5 = 2x - 2

y = 2x - 7