Question

find the zeroes of the polynomials 3t^2 - 7t, 2root5y^2 + y - 3root5​

Answer 1

Answer:

7/3

Step-by-step explanation:

3t^2 - 7t

T(3t-7)

T=0, 3t-7=0,.: t=7/3

The zeros are t=7/3

2root5y^2 +y-3 root 5

Pls does the root affect y tooo.