Answer:
[tex] \huge{ \fbox{ \sf{ \: (7.5 \:, 3.5)}}}[/tex]
Step-by-step explanation:
[tex] \star{ \sf{ \: Let \: the \: points \: be \: A\: and \: B}}[/tex]
[tex] \star{ \sf{ \: Let \:A(-5,5) \: be \: (x1 \:, y1) \: and \: B(-10,2) \: be \: (x2 ,\: y2)}}[/tex]
[tex] \underline{ \text{To \: find}} : \sf{Midpoint}[/tex]
[tex] \underline{ \underline{ \mathfrak{Let's \: solve}}} : [/tex]
[tex] \boxed{ \sf{Midpoint = ( \frac{x1 + x2}{2} ,\: \frac{y1 + y2}{2} )}}[/tex]
[tex] \hookrightarrow{ \sf{ \: Midpoint = ( \frac{ - 5 + ( - 10)}{2} \:, \frac{5 + 2}{2} }})[/tex]
[tex] \text{ \underline{ Remember!}} : \sf ( + ) \times ( - ) = ( - )[/tex]
[tex] \hookrightarrow{ \sf{Midpoint = ( \frac{ - 5 - 10}{2 } \:, \frac{5 + 2}{2}}} )[/tex]
[tex] \text{ \underline{Remember!}} : \sf{The \: negative \: integers \: are \: always \: added \: but \: posses \: the \: negative \: ( - ) \: sign.}[/tex]
[tex] \hookrightarrow{ \sf{Midpoint \: = \: ( \frac{ - 15}{2} \:, \frac{7}{2} }})[/tex]
[tex] \hookrightarrow{ \sf{Midpoint = ( \: 7.5 ,\: 3.5}})[/tex]
Hope I helped!
Best regards! :D
~[tex] \sf{TheAnimeGirl}[/tex]
