Question

A particle of mass 2 g travel a distance of 12 m in a time travel of 2 minute assuming the speed was constant find its kinetic energy?

Answer 1

Answer:

0.00001 J

Explanation:

$k.e = \frac{1}{2} m {v}^{2} \\ = \frac{1}{2} (0.002) { ( \frac{12}{120} )} ^{2} \\ = 0.00001j$