2
Type the correct answer in the box. Use numerals instead of words.
A ball is kicked with an initial height of 0.75 meters and initial upward velocity of 22 meters/second. This inequality represents the time, t in
seconds, when the ball's height is greater than 10 meters.
-4.9t2 + 22t + 0.75 > 10
and
seconds.
The ball's height is greater than 10 meters when t is approximately between blank and blank seconds

Respuesta :

Answer:

t is between 0 seconds and 4.878

Step-by-step explanation:

Given:

Inequality: [tex]-4.9t^2 + 22t + 0.75 > 10[/tex]

Required

Determine the value(s) of t

To answer this question, we simply solve the inequality

[tex]-4.9t^2 + 22t + 0.75 > 10[/tex]

Subtract 10 from both sides

[tex]-4.9t^2 + 22t + 0.75 - 10> 10 - 10[/tex]

[tex]-4.9t^2 + 22t -9.25> 0[/tex]

Multiply through by -1

[tex]4.9t^2 - 22t + 9.25 < 0[/tex]

Solve the value of t using quadratic formula

[tex]t = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}[/tex]

Where

a = 4.9; b = -22 and c = -9.25

So:

[tex]t = \frac{-(-22) \± \sqrt{(-22)^2 - 4 * 4.9 * -9.25}}{2 * 4.9}[/tex]

[tex]t = \frac{22 \± \sqrt{484 + 181.3}}{9.8}[/tex]

[tex]t = \frac{22 \± \sqrt{665.3}}{9.8}[/tex]

[tex]t = \frac{22 \± 25.80}{9.8}[/tex]

Split the expression

[tex]t = \frac{22 + 25.80}{9.8}[/tex]    or      [tex]t = \frac{22 - 25.80}{9.8}[/tex]

[tex]t = \frac{47.8}{9.8}[/tex]    or     [tex]t = \frac{-3.8}{9.8}[/tex]

[tex]t = 4.878[/tex]   or  [tex]t = -0.388[/tex]

Since t cannot be negative; Then

[tex]t < 4.878[/tex]

Hence; t is between 0 seconds and 4.878

TJM11

Answer:

c

Step-by-step explanation:

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