Recall that the slope of a non-vertical line is a measure of the number of units the line rises (or falls) vertically for each unit of horizontal change from left to right. Thus, the slope of a line passing through P(-2, 4) and Q(x, f(x)) is given by Slope = m =f(x)-4/x+2Thus, to find the slope of the secant lne passing through P(-2, 4) and Q-3, 3.), substitute for x in the equation m-(x + 2).

Respuesta :

Answer:

Slope m = -(x+2)

The Slope of the secant m = 1

Step-by-step explanation:

From the given information:

The slope of the line passing through P(-2,-4) and Q ( x, f(X)) can be calculated as :

Slope m = [tex]\dfrac{f(x) - 4}{x+2}[/tex]

Slope m = [tex]\dfrac{-4x-x^2-4}{x+2}[/tex]

Slope m = [tex]\dfrac{-(x^2+4x+4)}{x+2}[/tex]

Slope m = [tex]\dfrac{-(x+2)^2}{(x+2)}[/tex]

Slope m = -(x+2)

Passing through P(-2,4) and Q(-3,3)

Slope of the secant m = -(x+2)

Slope of the secant m  = -(-3 +2)

Slope of the secant m =  -( -1)

The Slope of the secant m = 1