Answer:
Slope m = -(x+2)
The Slope of the secant m = 1
Step-by-step explanation:
From the given information:
The slope of the line passing through P(-2,-4) and Q ( x, f(X)) can be calculated as :
Slope m = [tex]\dfrac{f(x) - 4}{x+2}[/tex]
Slope m = [tex]\dfrac{-4x-x^2-4}{x+2}[/tex]
Slope m = [tex]\dfrac{-(x^2+4x+4)}{x+2}[/tex]
Slope m = [tex]\dfrac{-(x+2)^2}{(x+2)}[/tex]
Slope m = -(x+2)
Passing through P(-2,4) and Q(-3,3)
Slope of the secant m = -(x+2)
Slope of the secant m = -(-3 +2)
Slope of the secant m = -( -1)
The Slope of the secant m = 1