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Answer:
The slope of the line would be 0.00910 in a logarithm graphic.
Step-by-step explanation:
Statement is incomplete. The correct sentences are: The increase in the number of humans living on Earth (N, as measured in billions) with time t (as measured in years since 1800) is modeld by the following function: N = 0.892e^0.00910t. If you were to graph in ln (N) versus t, what would be the slope of the line?
Let be [tex]N(t) = 0.892\cdot e^{0.00910\cdot t}[/tex], where [tex]N(t)[/tex] is the number of humans living on Earth, measured in billions, and [tex]t[/tex] is the time, measured in years since 1800. As we notice, this is an exponential function and its slope is not constant and such expression have to be linearized by using a logartihm graphic. We add logarithms on each side of the formula and simplify the resulting expression by means of logarithmic properties:
[tex]\log N(t) = \log \left(0.892\cdot e^{0.00910\cdot t}\right)[/tex]
[tex]\log N(t) = \log 0.892 + 0.00910\cdot t[/tex]
In a nutshell, the slope of the line would be 0.00910 in a logarithm graphic.
If we use the logarithmic scale on the y-axis, the slope would be 0.00919
How to get a line when graphing an exponential equation?
Here we know that N(t) is an exponential equation, but we want to get a line when we graph it, so what we should do is a change of scale.
Remember that:
Ln(e^x) = x
So, if we use the logarithmic scale in the y-axis (this means that we are actually graphing Ln(N(t)), but this is allowed) we will get:
Ln(0.892e^0.00910t)
Now remember that:
Ln(A) + Ln(B) = Ln(A*B)
Then:
Ln(0.892e^0.00910t) = Ln(0.892) + Ln(e^0.00919*t)
Ln(N(t)) = -0.114 + 0.00919*t
You can see that this is now a linear relation, and you can see that the slope is 0.00919
If you want to learn more about the logarithmic scale, you can read:
https://brainly.com/question/25867604