Question

A building with an interval volume of 12,450 ft3 experiences natural infiltration of 0.333 air change per hour. What is the infiltration rate in cubic meters per second?

Answer 1

Answer:

0.0326 m^3/s

Step-by-step explanation:

The interval volume V = 12450 ft^3

The natural infiltration I = 0.333 $hr^{-1}$

The infiltration rate = IV = 12450 x 0.333 = 4145.85 ft^3/hr

1 ft^3 = 0.0283168 m^3

1 hr = 3600 sec

4145.85 ft^3/hr = 4145.85 x (0.0283168/3600)

==> 0.0326 m^3/s