Question

An electric company calculates a person's monthly bill from the number of
kilowatt-hours (kWh), x, used,
x 200
The function b(ar) = {
0.102,
0.15(x - 200) +20, < > 200
determines the
bill
How much is the bill for a person who uses 600 kWh in a month?
A. $70
ООО
B, $60
C. $40
D. $80

Answer 1

Answer:

$80

Step-by-step explanation:

If a person's monthly bill from the number of  kilowatt-hours (kWh), x is modeled by the equation b = 0.15(x - 200) +20, to know the bill for a person who uses 600 kWh in a month, we will substitute x = 600 into the modeled equation as shown;

$b(x) = 0.15(x - 200) +20\\\\b(600) = 0.15(600 - 200) +20\\\\b(600 )= 0.15(400) +20\\\\b(600 )= 15/100*(400) +20\\\\b(600 )= (15*4)+20\\\\b(600 )= 60+20\\\\b(600 )= 80$

Hence the bill for a person who uses 600 kWh in a month is $80