Given :
A building is of unknown height. At a distance of 400 feet away from the building .
An observer notices that the angle of elevation to the top of the building is 35º and that the angle of elevation to a poster on the side of the building is 15º .
To Find :
How far is the poster from the roof of the building .
Solution :
Height is given by :
[tex]h=d\times tan\theta[/tex]
( Here , [tex]\theta[/tex] is angle of elevation )
So , height of tower :
[tex]H=400\times tan 35^o\\\\H=280.08 \ feet[/tex]
For height of poster :
[tex]h=400\times tan 15^o\\\\h= 107.18\ feet[/tex]
Therefore , distance of poster from the roof of the building is :
[tex]( 280.08-107.18) = $172.9\ feet[/tex]
Hence , this is the required solution .