Answer:
0.06546.
Step-by-step explanation:
Total number of tickets = 715
Good raffle tickets (Prize) = 4
Number of tickets bought = 12
[tex]\text{Probability of winning}=\dfrac{\text{Number of tickets bought}}{\text{Total raffle tickets}}[/tex]
[tex]\text{Probability of winning}=\dfrac{12}{715}[/tex]
[tex]\text{Probability of not winning}=1-\dfrac{12}{715}=\dfrac{703}{715}[/tex]
Let x be event of the number of winning prizes.
Probability that you will win at least 1 of the raffles is
[tex]P(x\geq 1)=1-P(x=0)[/tex]
[tex]P(x\geq 1)=1-^{4}C_0\left(\dfrac{12}{715}\right)^0\left(\dfrac{703}{715}\right)^{4-0}[/tex]
[tex]P(x\geq 1)=1-\left(\dfrac{703}{715}\right)^{4}[/tex]
[tex]P(x\geq 1)=1-0.93454[/tex]
[tex]P(x\geq 1)=0.06546[/tex]
Therefore, the required probability is 0.06546.
