Question

An isolated system contains two objects with charges q1q1 and q2q2. If the charge on object 1 is doubled, what is the charge on object 2? g

Answer 1

Answer:

The new charge on the second object is q₂ - q₁

Explanation:

Given;

charge on the first object,  q₁

charge on the second object, q₂

Since there is no external force on isolated system, the total charge in the system is given by;

Q = q₁ + q₂

q₂ = Q - q₁

When the charge on object 1 is doubled, q₁' = 2q₁

let q₂' be the new charge on object 2

q₂' = Q - q₁'

q₂' = (q₁ + q₂) - 2q₁

q₂' = q₁ + q₂ - 2q₁

q₂' = q₂ - q₁

Therefore, the new charge on the second object is q₂ - q₁

Answer 2

The charge on object 2 will be "q₂ - q₁".

Charge on object:

The charge's quantity on such an item represents the degree of imbalance between its electrons as well as protons.

Just to calculate the overall charge of a positively (+) charged item, divide the total no. of valence electrons by the overall number of protons.

According to the question,

Object 1's charge = q₁

Object 2's charge = q₂

Let,

New charge of object 2 be "q₂'".

 

The total charge in the system will be:

Q = q₁ + q₂

or,

q₂ = Q - q₁

hence,

The charge on object 2 be:

→ q₂' = Q - q₁'

By substituting the values,

        = (q₁ + q₂) - 2q₁

        = q₁ + q₂ - 2q₁

        = q₂ - q₁                

Thus the answer above is appropriate.

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