Question

What is the magnitude of total charge of all the electrons in 1.2 L of liquid water?

Answer 1

Answer:

6.416*10^ 8C

Explanation:

First we find mass of the water

Mass= density x volume

=1.2*1000= 1200g

To find number of moles we use

N= mass/ molar mass

= 1200/18.02= 66.6mol

So the total number of water molecules is

66.6* 6.022*10^23= 401.07x 10^23moles

But each h20 moles has 10 electrons so it will be 4.01*10^26electrons

Then finally total charge will be

4.01*10^26electrons x 1.6*10^-19

= 6.416*10^ 8C

Answer 2

The magnitude of total charge will be "6.416×10⁸ C".

Electrons:

According to the question,

Density, d = 1.2 L

Volume, V = 1000

The mass will be:

→ Mass = Density × Volume

By substituting the values,

            = $1.2\times 1000$

            = $1200$ g

Now,

The number of moles will be:

→ N = $\frac{Mass}{Molar \ mass}$

      = $\frac{1200}{18.02}$

      = $66.6$ mol

The total no. of water molecules be:

= $66.6\times 6.022\times 10^{23}$

= $401.07\times 10^{23}$ moles

hence,

The total charge be:

= $4.01\times 10^{26}\times 1.6\times 10^{-19}$

= $6.416\times 10^8$ C

Thus the above response is correct.

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