Question

A small mailbag is released from a helicopter that is descending steadily at 1.20 m/s. (a) After 5.00 s, what is the speed of the mailbag?

Answer 1

Answer:

50.2m/s

Explanation:

Using first equation of motion we have

V= u+gt

V= final speed

U= initial speed

So v = 1.2m/s + 9.8(5s)

50.2m/s