Answer:
56
Step-by-step explanation:
The sum of two even consecutive integers is 114.
Let's let the first even integer be 2n, where n is some integer: it doesn't matter what n is, but if we multiply n by 2, we are certainly getting an even number. This is because any integer multiplied by 2 is even.
So, this means that the second number is 2n+2.
Their sum is 114. In other words:
[tex](2n)+(2n+2)=114[/tex]
Solve for n.
Combine like terms:
[tex]4n+2=114[/tex]
Subtract 2 from both sides:
[tex]4n=112[/tex]
Divide both sides by 4:
[tex]n=28[/tex]
So, n is 28.
This means that the first number is 28(2) or 56.
And the second number is 58.
So, the smallest integer is 56.
And we're done!