Question

A certain ore is 20.7% nickel by mass. How many kilograms of this ore would you need to dig up to have 70.0 g of nickel?

Answer 1

Answer:

0.3382 kg

Explanation:

From the illustration:

100g of the ore would contain 20.7 g of nickel by mass. In order to obtain 70.0 g of nickel, the amount of the ore needed would be:

          100 x 70.0/20.7 = 338.16 g

According to conversion units:

1 g = 0.001 kg

Hence,

338.16 g = 338.16 x 0.001 = 0.3382 kg

Therefore, 0.3382 kg of the ore would be required in order to obtain 70.0 g of nickel.

Answer 2

Amount of core in Kilogram is 0.338 kg (Approx.)

Given that;

Percentage in every ore = 20.7%

Amount of nickel = 70 gram

Find:

Amount of core in Kilogram

Computation:

Amount of core in Kilogram = Amount of nickel / Percentage in every ore

Amount of core in Kilogram = 70 / 20.7%

Amount of core in Kilogram = 70 / 0.207

Amount of core in Kilogram = 338.16 gram

Amount of core in Kilogram = 0.338 kg (Approx.)

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