Question

NEED HELP FAST!!! Determine the momentum: An electron (m= 9.1 x 10-31 kg) moving at 2.18 x 106 m/s (as if it were in a Bohr orbit in the H atom)

Answer 1

Answer:

p= (9.1 x 10^-31)(2.18 x 10^6)   p = 1.9 x 10^-22kg*m/s

Step-by-step explanation:

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Answer 2

The momentum of electron is $1.9\times 10^{26}$ kg m per second.

Given, mass of electron is $9.1\times 10^{-31}$ kg.

And its velocity is $2.18 \times 10^6$ m per s.

We have to calculate its momentum.

We know that momentum is numerically equal to the product of mass and velocity of a particle and denoted by p.

So, $p=mv$

$p= 9.1\times10^{-31}\times2.18\times10^{6}$

$p=19.838\times10^{25}$

$p=1.9\times10^{26}$

Hence the momentum of electron is $1.9\times 10^{26}$ kg m per second.

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