Answer:
All the objects experience the same acceleration
Explanation:
According to Newton's law of universal gravitation, we have the gravitational force F given by the relation;
[tex]F=G \times \dfrac{M_1 \times m_{2}}{R^{2}}[/tex]
Where;
G = The universal gravitational constant
M₁ = The mass of the Earth
m₂ = The mass of the object in the Earths gravitational field
R = The radius of the Earth
Therefore, we have;
[tex]F= m_2 \times a = G \times \dfrac{M_1 \times m_{2}}{R^{2}}[/tex]
Which gives;
[tex]a = G \times \dfrac{M_1 }{R^{2}} \ which \ is \ a \ constant = 9.80665 \ m/s^2, \ known \ as \ g, \ which \ is \ \\the \ (acceleration \ due \ to \ gravity)\\[/tex]Therefore, based on the above calculation, all three object will have the same acceleration due to gravity, g, when air resistance is ignored.