Question

What is the specific gravity of mercury, the liquid used in thermometers, if it has a density of
13.6 g/mL?

Answer 1

Answer:

13.64.

Explanation:

Hello,

In this case, since the the specific gravity is computed as the ratio of the density of the given substance by the density of water that is approximately 0.997 g/mL as shown below:

$s.g=\frac{\rho}{\rho _{water}}$

In such a way, for this case, we find:

$s.g=\frac{13.6g/mL}{0.997g/mL}=13.64$

Which is dimensionless due the g/mL simplification.

Best regards.

Answer 2

The specific gravity of mercury is 13.61

Specific gravity is defined as the ratio of the density of a substance to the density of water. Mathematically;

$sg=\frac{\rho_s}{\rho_{water}}$

Given the following parameters:

$\rho_{Hg}=13.6g/mL\\\rho_{H_2O}=0.9998g/mL$

Substitute the given parameters into the formula;

$sg=\frac{13.6g/mL}{0.9998g/mL}\\sg=13.61$

Hence the specific gravity of mercury is 13.61

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