Question

Write the inverse of f(x) = 3x - 1
f -1(x) =

log 3 x + 1
log 3 ( x - 1)
log 3 x - 1

Answer 1

Step-by-step explanation:

Firstly, the inverse of f(x) exists because f(x) is an injective and surjective function.

y = 3x - 1

3x = y + 1

x = 1/3 * (y + 1)

Therefore inverse of f(x) = 1/3 * (x+ 1).

I do not see any log here so let me know if there's addition information!

Answer 2

Answer:

log 3 x +1 = f^-1(x)=$\frac{10^x^-^1}{3}$

log 3 (x-1) = f^-1(x)=$\frac{x}{log(3)} +1$

log 3 x - 1 = f^-1=$\frac{10^x^+^1}{3}$