Question

The density of gold is 19.3 grams per milliliter. What would that be in pounds per cup?

Answer 1

Answer:

$\rho =10.07\frac{lb}{cup}$

Explanation:

Hello,

In this case, given that 1 cup equals 236.588 mL and 1 pound equals 453.6 g, the required density in pounds per cup turns out:

$\rho =19.3\frac{19.3g}{mL}*\frac{1lb}{453.6g}*\frac{236.588mL}{1cup}\\ \\\rho =10.07\frac{lb}{cup}$

Best regards.