Question

A rectangular parking lot has a length that is 10 yards greater than the width. The area of the parking lot is 600 square yards. Find the length and the width

Answer 1

Step-by-step explanation:

Let x be the width of the parking lot. Then (x + 10) is the length of the parking lot.

x(x + 10) = 600

x^2 + 10x = 600

x^2 + 10x - 600 = 0

(x+30)(x-20) = 0

x = 20 or x = -30 (rejected as x must be positive)

Hence the length is 30 yards and the width is 20 yards.