Question

C is the midpoint of segment AB. Find the value of m+k.

A(-3,m)

B (4, -1)

C (k, 2)

Answer 1

Answer:

The value of m + k = $5+\frac{1}{2}$ = $\frac{11}{2}$.

Step-by-step explanation:

We are given that C is the midpoint of segment AB where A(-3,m) , B (4, -1) , and C (k, 2).

As we know that the mid-point formula states that;

Mid-point = $\frac{a+b}{2}$

This means that;

Mid-point of AB = $\frac{A+B}{2}$

C(k, 2) = $(\frac{-3+4}{2}, \frac{m+(-1)}{2} )$

C(k, 2) = $(\frac{1}{2}, \frac{m-1}{2} )$

This means that;

$k = \frac{1}{2}$  and  $2=\frac{m-1}{2}$

$k = \frac{1}{2}$  and  $m-1=4$

$k = \frac{1}{2}$  and  $m = 4+1 = 5$

So, the value of m + k = $5+\frac{1}{2}$ = $\frac{11}{2}$.