Question

A freight train, traveling at a speed of 18.0 m/s, begins braking as it approaches a train yard. The train's acceleration while braking is –0.33 m/s2 . What is the train's speed after 23s?

Answer 1

Answer:

v = 10.41 m/s

Step-by-step explanation:

using one of the equations of motion:

v = u + at

where v= final velocity

u= initial velocity

a = acceleration

t = time

u = 18.0 m/s

v = ?

a = –0.33 m/s2

t = 23s

v = 18.0 + (–0.33 x  23)

v = 18.0 + (-7.59)

v = 10.41 m/s