Question

The atomic mass number of aluminum is 26.98. If you had 1.34 x 1025 atoms of aluminum, how much would they all weigh?
3.62 grams
601 grams
3.62 x 1026 grams
1.21 grams

Answer 1

Answer:

601 gram

Explanation:

1st we should know how may moles are there in 1.34 X 10 25 atoms

 # moles of Al = # of atoms / # of Avogadro's num

                      = 1.34 X 10 25/ 6.12X10 23 =

                       = 22.26 mol of AL

 so mass of AL = moles x m.wt

                          =22.26 x 26.98 = 600.55 = 601 gram

DONE