Question

Two forces are given by j = (-2,1] and K = (-5,3), in
Newtons. What is the magnitude of j+k ?

Answer 1

Answer:

$\sqrt{65}$

Step-by-step explanation:

The magnitude of a vector < x, y > is calculated as

| < x, y > | = $\sqrt{x^2+y^2}$

Thus

j + k = < - 2, 1 > + < - 5, 3 > = < - 2 - 5, 1 + 3 > = < - 7, 4 >

Then

| < - 7, 4 > | = $\sqrt{(-7)^2+4^2}$ = $\sqrt{49+16}$ = $\sqrt{65}$