Question

A rectangle length is 5 more than its width. If the premiditer of the rectangle is 66 inches, what is the length of the rectangle

Answer 1

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{19 \: inches}}}}}$

Step-by-step explanation:

Let the width be 'w'.

Length of a rectangle ( l ) = 5 + w

Perimeter of a rectangle = 66 inches

First, finding the width of a rectangle

$\boxed{ \sf{perimeter \: of \: rectangle = 2(l + w)}}$

$\dashrightarrow{ \sf{66 = 2(5 + w + w)}}$

$\dashrightarrow{ \sf{66 = 2(5 + 2w)}}$

$\dashrightarrow{ \sf{66 = 10 + 4w}}$

$\dashrightarrow{ \sf{10 + 4w = 66}}$

$\dashrightarrow{ \sf{4w = 66 - 10}}$

$\dashrightarrow{ \sf{4w = 56}}$

$\dashrightarrow{ \sf{ \frac{4w}{4} = \frac{56}{4} }}$

$\dashrightarrow{ \sf{w = 14 \: inches}}$

Width of a rectangle ( w ) = 14 inches

Now, Substituting / Replacing the value of w in order to find the length of rectangle

$\sf{length = 5 + w}$

$\dashrightarrow{ \sf{length = 5 + 14}}$

$\dashrightarrow{ \sf{19 \: inches}}$

Length of a rectangle = 19 inches

Hope I helped!!

Best regards! :D