Question

-1
The distance AB
rounded to the
nearest tenth = [?]
Help Resources
-2
-1
0
Skip
B
Hint: Use the distance formula:
d = (x2 – X1)2 + (y2 - yı)?
Enter

Answer 1

Answer:

AB = 4.5

Step-by-step explanation:

Distance between A(-1, 2) and B(1, -2):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-1, 2) = (x_1, y_1)$

$B(1, -2) = (x_2, y_2)$

$AB = \sqrt{(1 - (-1))^2 + (-2 - 2)^2}$

$AB = \sqrt{(2)^2 + (-4)^2}$

$AB = \sqrt{4 + 16} = \sqrt{20}$

$AB = 4.5$ (nearest tenth)