Question

Order of operations A set of three scores consists of the values 6, 3, and 2. 1. Σ2X – 2 =______.a. 35.b. 33.c. 22.d. 6.2. Σ(2X)² =______.a. 248.b. 124.c. 61.d. 39.

Answer 1

Answer:

Step-by-step explanation:

Given the order of operations A set of three scores to consists of the values 6, 3, and 2, we are to evaluate the following

1) Σ2X – 2

= 2(6)+2(3)+2(2) – 2

= 12+6+4–2

= 22–2

= 20

2) Σ(2X)² = (2×6)²+(2×3)²+(2×2)²

Σ(2X)² = 12²+6²+4²

Σ(2X)² = 144+36+16

Σ(2X)² = 144+52

Σ(2X)² = 196

Answer 2

The results of the order of operations are: $\sum 2x -2 = 16$ and $\sum (2x)^2 =196$

The scores are given as:

x = 6, 3 and 2

(a) The first set of operation

This is represented as:

$\sum 2x -2$

So, we have:

$\sum 2x -2 = 2 \times 6 - 2 + 2 \times 3 - 2 + 2 \times 2 - 2$

Evaluate the products

$\sum 2x -2 = 12 - 2 + 6 - 2 + 4- 2$

$\sum 2x -2 = 16$

(a) The second set of operation

This is represented as:

$\sum (2x)^2$

So, we have:

$\sum (2x)^2 =(2 \times 6)^2 + (2 \times 3)^2 + (2 \times 2)^2$

Evaluate the products

$\sum (2x)^2 =12^2 + 6^2 + 4^2$

Evaluate the squares

$\sum (2x)^2 =144 + 36 + 16$

$\sum (2x)^2 =196$

Hence, the results of the order of operations are:

$\sum 2x -2 = 16$ and $\sum (2x)^2 =196$

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