Question

The acceleration of a particle traveling along a straight line is
a=16s1/2 m/s2, where s is in meters.
If v = 0, s = 3 m when t = 0, determine the particle's velocity at s = 6 m.

Answer 1

Answer:

V= 14.2m/s

Explanation:

We know that acceleration= dv/dt

So 16m/s²=dv/ dt = v dv/ds

So this wil be

Integral of 16m/s² ds [at 2,2]= integral of v dv at[ 0, v]

So 16[s (3/2)/3/2] at ( s,3) = v²/2

At s= 6m

So v² = 64/3( 6^1.5-3^1.5)

= 14.2m/s