Question

The sum of two numbers is 24. One is 6 less than twice the other. Find the two numbers.

(apply polya's problem solving method)​

Answer 1

Answer:

$\huge\boxed{\sf x = 14 , y = 10}$

Step-by-step explanation:

Let the two numbers be x and y

Condition # 1:

x + y = 24  ---------------------(1)

Condition # 2:

x = 2y - 6  ----------------------(2)

$\rule[225]{225}{2}$

Putting Equation # 2 in Equation # 1

2y - 6 + y = 24

3y - 6 = 24

Adding 6 to both sides

3y = 24 + 6

3y = 30

Dividing both sides by 3

y = 10

$\rule[225]{225}{2}$

Putting y = 10 in Equation # 2

x = 2y - 6

x = 2(10) - 6

x = 20 - 6

x = 14

$\rule[225]{225}{2}$

Answer 2

The two numbers are 10 and 14.

The sum of 2 numbers is 24.

let the number be x and y . Therefore,

x + y = 24

One is 6 less than twice the other. therefore,

2x - y = 6

Combine the equations

x + y = 24

2x - y = 6

3x = 30

x = 30 / 3

x = 10

x + y = 24

10 + y = 24

y = 24 - 10

y = 14

The 2 numbers are 10 and 14 .

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