Question

A crowbar of 2m is used to lift an object of 800N. If the effort is 160m, calculate the effort applied.
Plz give full process answer. I want it soon. ​

Answer 1

Answer:

It's of science not of mathematics

Answer 2

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{10 \: N}}}}}$

Step-by-step explanation:

Given,

Load distance ( LD ) = 2m

Load ( L ) = 800 N

Effort distance ( ED ) = 160 m

Effort ( E ) = ?

Finding the Effort applied

Apply the principal of simple machine :

$\boxed{ \sf{L \times LD = E\times ED}}$

$\longrightarrow{ \sf{800 \times 2 = E \times 160}}$

$\longrightarrow{ \sf{1600 = 160 \: E}}$

$\longrightarrow{ \sf{160E = 1600}}$

$\longrightarrow{ \sf{ \frac{160E}{160} = \frac{1600}{160} }}$

$\longrightarrow{ \sf{E = 10 \: \: newton}}$

Effort applied = 10 N

Hope I helped!

Best regards! :D