Question

Please I need help with this question!!

Answer 1

[15 + 1/2 ] - [ 2 + 3/4 ] - [6 + 2/3 ]......convertng these to improper fractions, we have

[31 /2 ] - [11 / 4 ] - [ 20 / 3 ] getting a common denominator (12), we have

[186 / 12] - [33 / 12 ] - [ 80 / 12 ] = 73 / 12 inches = about 6.0833 inches left

Answer 2

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{6 \frac{1}{12} \: \: \: inches}}}}}$

Step-by-step explanation:

Total inches of a green ribbon = $\sf{15 \frac{1}{2} }$

Finding the total inches of ribbon that she cut off

$\sf{2 \frac{3}{4} + 6 \frac{2}{3} }$

Convert the mixed number into an improper fraction

$\dashrightarrow{ \sf{ \frac{2 \times 4 + 3}{4} + \frac{3 \times 6 + 2}{3}}}$

$\dashrightarrow{ \sf{ \frac{8 + 3}{4} + \frac{18 + 2}{3} }}$

$\dashrightarrow{ \sf{ \frac{11}{4} + \frac{20}{3} }}$

Take the L.C.M ( Least Common Multiple ) of 4 and 3

L.C.M = 4 and 3 = 12

$\dashrightarrow{ \sf{ \frac{11 \times 3 + 20 \times 4}{12} }}$

$\dashrightarrow{ \sf{ \frac{33 + 80}{12}}}$

$\dashrightarrow{ \sf{ \frac{113}{12} }}$

Total inches of ribbon that she cut off = 113/12

Now, finding the left inches of ribbon

$\sf{15 \frac{1}{2} - \frac{113}{12} }$

Convert mixed number into improper fraction

$\dashrightarrow{ \sf{ \frac{15 \times 2 + 1}{2} - \frac{113}{12} }}$

$\dashrightarrow {\sf{ \frac{31}{2} - \frac{113}{12} }}$

Take the L.C.M of 2 and 12 , you will get 12

$\dashrightarrow{ \sf{ \frac{31 \times 6 - 113}{2} }}$

$\dashrightarrow{ \sf{ \frac{186 - 113}{12}}}$

$\dashrightarrow{ \sf{ \frac{73}{12} }}$

Convert the improper fraction into mixed number

$\dashrightarrow{ \sf{6 \frac{1}{12} }}$ inches

Hope I helped!

Best regards! :D