Question

find the vertex of y=x^2-6x+1 A. ( 1 , 5 ) B. ( 4 , 1 ) C. ( 2 , -3 ) D. ( 3 , -8)

Answer 1

$h=\frac{-b}{2a}$

$k=f(h)$

$h=\frac{6}{2}$

$h=3$

$k=f(3)$

$f(3)=9-18+1$

$f(3)=-8$

The vertex is $(3,-8)$

Hope this helps.

頑張って!