Question

smbdy plssss I'll give 35 points
An estate agent has three houses for sale. The prices of the houses were
in the ratio 6:4:3 and the cheapest house was priced at $240 000. What
were the prices of the other two houses? (SHOW WORKING)​

Answer 1

Answer:

Step-by-step explanation:

sum of ratio=6+4+3=13

let the total price of houses=x

then

$\frac{3}{13} x=240,000\\x=240,000 \times \frac{13}{3} =1,040,000\\price of first house=1,040,000 \times \frac{6}{13} =480,000\\price~of~second~house=1,040,000 \times \frac{4}{13}=320,000$