Question

if f(x)=4x^2-6

find all x such that f(x)= 106

Answer 1

Answer:

50

Step-by-step explanation:

Answer 2

Answer:

$2\sqrt7,-2\sqrt7$

Step-by-step explanation:

So we have the function:

$f(x)=4x^2-6$

And we want to find all x such that f(x) is 106. So, substitute 106 for f(x):

$106=4x^2-6$

Add 6 to both sides:

$112=4x^2$

Divide both sides by 4:

$x^2=28$

Take the square root of both sides:

$x=\pm\sqrt{28}$

Simplify the square root:

$x=\pm\sqrt{28}=\pm\sqrt{4\cdot 7}=\pm2\sqrt7$

So, those are the two values that will satisfy our requirement.

And we're done!