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Eduard22sly

Answer:

2.12×10²³ atoms.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ atoms. This simply means that 1 mole of zirconium also 6.02×10²³ atoms.

Thus, we can obtain the number of atoms present in 0.3521 mole of zirconium as follow:

1 mole of zirconium also 6.02×10²³ atoms.

Therefore, 0.3521 mole of zirconium will contain = 0.3521 × 6.02×10²³ = 2.12×10²³ atoms.

Therefore, 0.3521 mole of zirconium contains 2.12×10²³ atoms.

samueladesida43

There are 2.12 × 10²³ atoms of zirconium in 0.3521 mol of zirconium.

HOW TO CALCULATE NUMBER OF ATOMS:

  • The number of atoms of zirconium can be calculated by multiplying the number of moles in the element with Avogadro's number. That is;

  • no. of atoms in Zirconium = no. of moles = 6.02 × 10²³

  • According to this question, 0.3521 mol of zirconium was given. The number of atoms can be calculated as follows:

  • no. of atoms of Zirconium = 0.3521 × 6.02 × 10²³

  • no. of atoms of Zirconium = 2.12 × 10²³ atoms.

  • Therefore, there are 2.12 × 10²³ atoms of zirconium in 0.3521 mol of zirconium.

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