Answer:
[tex]\frac{ML}{T^2}=\frac{ML}{T^2}[/tex]
Hence it is proved that Stokes-Oseen formula is dimensionally homogenous.
Explanation:
For equation to be dimensionally homogeneous both side of the equation must have same dimensions.
For given Equation:
F= Force, μ= viscosity, D = Diameter, V = velocity, ρ= Density
Dimensions:
[tex]F=\frac{ML}{T^2}[/tex]
[tex]\mu=\frac{M}{LT}[/tex]
[tex]D=L\\\\V=\frac{L}{T}\\ \\\rho=\frac{M}{L^3}[/tex]
Constants= 1
Now According to equation:
[tex]\frac{ML}{T^2}=[\frac{M}{LT}][L] [\frac{L}{T}] + [\frac{M}{L^3}][\frac{L^2}{T^2}][L^2][/tex]
Simplifying above equation, we will get:
[tex]\frac{ML}{T^2}=2*\frac{ML}{T^2}[/tex]
Ignore "2" as it is constant with no dimensions. Now:
[tex]\frac{ML}{T^2}=\frac{ML}{T^2}[/tex]
Hence it is proved that Stokes-Oseen formula is dimensionally homogenous.