Question

An outdoor spigot at the school has a leak and is dripping water. A student counted eighty drops of water in five minutes and noticed that sixty drops of water filled a container to a level of ten milliliters. If the spigot is not fixed and this dripping rate continues, how many liters of water will be wasted in four weeks? Round the answer to the nearest liter.

Answer 1

Answer:

108 liters

Step-by-step explanation:

Given that:

80 drops are there in 5 minutes.

Time to be considered is 4 weeks.

Let us find number drops in 4 weeks.

Number of drops in 5 minutes = 80

Number of drops in 1 minute = $\frac{80}{5}$

Number of drops in 60 minutes = $\frac{80}{5}$ $\times 60$

Number of drops in 24 hours (60 $\times$ 24 minutes) = $\frac{80}{5}$ $\times 60$ $\times 24$

Number of drops in 28 days (28 $\times$24 hours OR 60 $\times$ 24 $\times$28 minutes) = $\frac{80}{5}$ $\times 60$ $\times 24$$\times$28 = 645120

Now, we are given that 60 drops = 10 mL

1 drop = $\frac{10}{60}$ mL

645120 drops = $\frac{10}{60} \times 645120$ =  107520 mL

We know that 1000 mL = 1 Liter

1 mL =  $\frac{1}{1000}$ Liter

107520 mL = $\frac{1}{1000} \times 107520\ L \approx 108\ L$

So, the answer is 108 Liter.