Question

In the Bohr theory of the hydrogen atom, an electron moves in a circular orbit about a proton, assume the radius of the orbit is 5.29 10-11 m.
A) Find the magnitude of the electric force exerted on each particle.B) If this force causes the centripetal acceleration of the electron, what is the speed of the electron?

Answer 1

Answer:

Explanation:

Force between two charged particle having charge q₁ and q₂ at distance r

F = k q₁ x q₂ / r²

Putting the values

F = 9 x 10⁹ x 1.6 x 10⁻¹⁹ x 1.6 x 10⁻¹⁹ / 5.29² x 10⁻²²

= .823 x 10⁻⁷

= 823 x 10⁻¹⁰ N

This force will apply on both the charges and will be attractive in nature .

B )

Let speed of electron be v

centripetal force on electron = F

m v² / r = 823 x 10⁻¹⁰

putting the values for electron

9.1 x 10⁻³¹ x v² / 5.29 x 10⁻¹¹ = 823 x 10⁻¹⁰

v² = 478.42 x 10¹⁰

v = 21.87 x 10⁵ m /s