Question

Clint and Jim rode their bicycles to Mill Park at an average of 8 mi/hr. It took then 1 hr longer to return home riding at an average of 7 mi/hr on a route that was 4 mi longer than their route. How long were they riding their bicycles? How man miles did they ride each way?

Answer 1

Answer:

Total time for which they ride = $\bold{7\ hours}$

Number of miles they ride each way = 24 mi

Step-by-step explanation:

Average speed = 8 mi/hr

Let the Distance to Mill Park = $D$ mi

Let the time taken = $t$ hours

Formula:

$Distance = Speed \times Time$

$\Rightarrow D = 8t$ ..... (1)

Now, when average speed = 7 mi/hr

Time taken is 1 hour more, i.e. Time = $t+1$ hours

Distance traveled is 4 mi more, i.e. $D+4$ mi

Using the Formula:

$Distance = Speed \times Time$

$D+4=7\times (t+1)$

From equation (1):

$8t+4=7t+7\\\Rightarrow t=3\ hours$

From equation (1):

$D = 8 \times 3 = 24\ mi$

Total time for which they ride = $t+t+1 = \bold{7\ hours}$

Number of miles they ride each way = 24 mi