Question

3x^2 - 4x = 2

I have to solve the equation using the quadratic formula then write the answer in simplest form

Despite my many efforts, it's still marked as wrong, and photomath didnt get it right, either.​

Answer 1

Answer:

Step-by-step explanation:

3x^2 - 4x - 2 = 0

4/6 + (sqrt(16 - 4(3)(-2)))/6

2/3 + (sqrt(16+24))/6

2/3 + (sqrt(40))/6

2/3 + 2(sqrt(10)/6

2/3 + (sqrt(10))/3

Answer 2

Answer:

$x = \frac{2 + \sqrt{10} }{3} \: \: \: or \: \: \: x = \frac{2 - \sqrt{10} }{3}$

Step-by-step explanation:

3x² - 4x - 2 = 0

Using the quadratic formula

That's

$x = \frac{ - b\pm \sqrt{ {b}^{2} - 4ac } }{2a}$

From the question

a = 3 , b = - 4 , c = - 2

So we have

$x = \frac{ - - 4\pm \sqrt{( { - 4})^{2} - 4(3)( - 2)} }{2(3)} \\ x = \frac{4\pm \sqrt{16 + 24} }{6} \\ x = \frac{4\pm \sqrt{40} }{6} \\ x = \frac{4\pm2 \sqrt{10} }{6} \\ x = \frac{4}{6} \pm \frac{ 2\sqrt{10} }{6} \\ x = \frac{2}{3} \pm \frac{ \sqrt{10} }{3} \\ x = \frac{2\pm \sqrt{10} }{3}$

We have the final answer as

$x = \frac{2 + \sqrt{10} }{3} \: \: \: or \: \: \: x = \frac{2 - \sqrt{10} }{3}$

Hope this helps you