Question

Simplify (2^3)^–2 ment to put this

Answer 1

Answer:

$\frac{1}{64}$

Step-by-step explanation:

$\left(2^3\right)^{-2}\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0\\\left(2^3\right)^{-2}=2^{3\left(-2\right)}\\\\3\left(-2\right)=-6\\=2^{-6}\\\\\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\\2^{-6}=\frac{1}{2^6}\\\\2^6=64\\\\=\frac{1}{64}$

Answer 2

Answer:

1/64

Step-by-step explanation:

$\left(2^3\right)^{-2}\\\\\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\\\left(2^3\right)^{-2}=2^{3\left(-2\right)}\\\\3\left(-2\right)=-6\\\\=2^{-6}\\\\=\frac{1}{2^6}\\\\2^6=64\\\\=\frac{1}{64}$